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Contact Spring Calculations

Revision as of 07:55, 11 January 2023 by Doduco Admin (talk | contribs) (Reverted edits by Doduco Redaktion (talk) to last revision by STZAdmin)

Contact Spring Calculations

One side fixed contact bending spring

The influence of the dimensions can be illustrated best by using the single side fixed beam model Figure 1. For small deflections the following equation is valid:

$F = \frac{3 \cdot E \cdot J}{L^3} $

where J is the momentum of inertia of the rectangular cross section of the beam

$J = \frac{B \cdot D^3}{12}$

For springs with a circular cross-sectional area the momentum of inertia is

$J=\pi D^4/64$
$D= Durchmesser$

To avoid plastic deformation of the spring the max bending force σmax cannot be exceeded

$\sigma_{max} = \frac{3 \cdot E \cdot D}{2L^2}\cdot_{max}$

The stress limit is defined through the fatigue limit and the 0.2% elongation limit resp.

$\times_{max} = \frac{2 \cdot L^2}{3 \cdot D \cdot E}R_{p0,2}$


and/or

$F_{max} = \frac{B \cdot D^2}{6L}R_{p0,2}$


  • Special Spring Shapes
    • Triangular spring
    • Deflection

      $ \times = \frac{F}{2 \cdot E \cdot J}L^3$


      $= \frac{6 \cdot F}{E \cdot B}\cdot \frac{L^3}{D^3}$


      Max. bending force

      $\sigma_{max}= \frac{18 \cdot F \cdot L}{B \cdot D^2}$
    • Trapezoidal spring
    • Deflection

      $ \times = \frac{F}{(2 + B_{min} /B_{max})}\times \frac{L^3}{E \cdot J}$


      $\times= \frac{12 \cdot F}{(2 + B_{min} /B_{max})}\cdot \frac{L^3}{E \cdot B \cdot D^3}$


      Max. bending force

      $\sigma_{max}= \frac{18 \cdot F \cdot L}{(2 + B_{min} /B_{max}) \cdot B_{max} \cdot D^2 }$


    References